5x^2-7x=x(x-1)

Solution for 5x^2-7x=x(x-1) equation:

5x^2-7x=x(x-1)

We move all terms to the left:

5x^2-7x-(x(x-1))=0


We calculate terms in parentheses: -(x(x-1)), so:

x(x-1)

We multiply parentheses

x^2-1x

Back to the equation:

-(x^2-1x)


We get rid of parentheses

5x^2-x^2-7x+1x=0

We add all the numbers together, and all the variables

4x^2-6x=0

a = 4; b = -6; c = 0;
Δ = b2-4ac
Δ = -62-4·4·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-6}{2*4}=\frac{0}{8}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+6}{2*4}=\frac{12}{8}
=1+1/2
$